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Algebra 2 Complex Numbers: I, Conjugates and Division

Complex numbers in Algebra 2: what i is, adding, multiplying and dividing with conjugates, and solving quadratics with complex solutions.

  • ⏱ 3 min read
  • ✏️ 3 worked examples
  • 🎯 5 practice questions
  • 📶 Intermediate
High School

Curriculum fit: US Algebra 2. Aligned to the Common Core Complex Number System standards (HSN-CN.A and HSN-CN.C.7). Check your own state standards and course.

On this page

What Is It?

Some quadratic equations, such as x² = −1, have no real solution. To fix this, mathematicians define the imaginary unit i, where i² = −1.

A complex number has the form a + bi, where a is the real part and b is the imaginary part. You add and multiply them like algebraic expressions, replacing i² with −1.

To divide, multiply the top and bottom by the conjugate of the denominator. The conjugate of a + bi is a − bi, and (a + bi)(a − bi) = a² + b², which is a real number.

Definitioni² = −1Forma + biConjugatea − biProduct with conjugatea² + b² (real)
Replace i² with −1 after multiplying. Multiply by the conjugate to divide.

Key Formulas and Ideas

  • i² = −1, so i³ = −i and i⁴ = 1.
  • Add: (a + bi) + (c + di) = (a + c) + (b + d)i.
  • Multiply by expanding and replacing i² with −1.
  • Conjugate of a + bi is a − bi, and (a + bi)(a − bi) = a² + b².
  • Divide by multiplying top and bottom by the conjugate of the denominator.
  • Quadratic formula: x = (−b ± √(b² − 4ac)) ÷ 2a. A negative discriminant gives complex solutions.

Worked Examples

Example 1

Multiply Complex Numbers

Question

Multiply (3 + 2i)(1 − 4i).

  1. Expand: 3 − 12i + 2i − 8i².
  2. Replace i² with −1: −8i² = +8.
  3. Combine: (3 + 8) + (−12 + 2)i = 11 − 10i.

✓ Answer 11 − 10i

Example 2

Divide Complex Numbers

Question

Simplify (5 + i) ÷ (2 − i).

  1. Multiply top and bottom by the conjugate 2 + i.
  2. Top: (5 + i)(2 + i) = 10 + 5i + 2i + i² = 9 + 7i. Bottom: (2 − i)(2 + i) = 4 + 1 = 5.
  3. Divide each part by 5.

✓ Answer 9/5 + (7/5)i

Example 3

Complex Solutions of a Quadratic

Question

Solve x² + 4x + 13 = 0.

  1. Quadratic formula: x = (−4 ± √(16 − 52)) ÷ 2 = (−4 ± √−36) ÷ 2.
  2. √−36 = 6i.
  3. x = (−4 ± 6i) ÷ 2 = −2 ± 3i.

✓ Answer x = −2 + 3i or x = −2 − 3i

Common Mistakes to Avoid

  • Forgetting that i² = −1 after multiplying, which leaves an unwanted i².
  • Using the same sign instead of the opposite sign to make the conjugate.
  • Combining real and imaginary parts as if they were like terms.
  • Writing √−36 as −6. It is 6i.

Practice Questions

0 of 5 answered
Q1i² =
Q2i³ =
Q3(2 + 3i) + (1 − 5i) =
Q4The conjugate of 4 − 7i is…
Q5(1 + i)(1 − i) =

Frequently Asked Questions

Are imaginary numbers real?

They are not on the real number line, but they are a consistent part of mathematics. They are used in engineering, such as in electrical circuits and signal processing.

What is the conjugate of a complex number?

It is the same number with the sign of the imaginary part changed. The conjugate of 4 − 7i is 4 + 7i.

Why do complex roots come in pairs?

For a quadratic with real coefficients, the ± in the quadratic formula gives a pair of conjugates, such as −2 + 3i and −2 − 3i.

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Sources and Review

Reviewed by StudyMorrow editorial review on 6 Nov 2026.