Curriculum fit: GCSE Chemistry and Combined Science (quantitative chemistry; mole calculations are mainly Higher tier). US: high school and AP Chemistry (stoichiometry).
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What Is It?
A mole is an amount of substance containing 6.02 × 10²³ particles (Avogadro's number). The mass of one mole in grams equals the relative formula mass (Mr).
Moles let you link the masses of reactants and products in a balanced equation, and work out concentrations of solutions.
Key Formulas and Ideas
- moles = mass ÷ Mr (mass in grams).
- mass = moles × Mr.
- concentration (mol/dm³) = moles ÷ volume in dm³.
- Mr = sum of the relative atomic masses of all atoms in the formula.
Worked Examples
Mr and Mass
Find the mass of 0.25 mol of calcium carbonate, CaCO₃ (Ar: Ca 40, C 12, O 16).
- Mr = 40 + 12 + 3 × 16 = 100.
- mass = 0.25 × 100 = 25.
✓ Answer 25 g
Reacting Masses
6 g of magnesium burns in oxygen: 2Mg + O₂ → 2MgO. Find the mass of magnesium oxide made (Ar: Mg 24, O 16).
- Moles of Mg = 6 ÷ 24 = 0.25.
- The ratio Mg : MgO is 1 : 1, so 0.25 mol MgO.
- Mr of MgO = 40, so mass = 0.25 × 40 = 10 g.
✓ Answer 10 g
Concentration
2 mol of a substance is dissolved to make 4 dm³ of solution. Find the concentration.
- Concentration = moles ÷ volume.
- 2 ÷ 4 = 0.5.
✓ Answer 0.5 mol/dm³
Common Mistakes to Avoid
- Using the mass in kilograms instead of grams.
- Forgetting to use the balanced equation ratio.
- Not converting cm³ to dm³ by dividing by 1000.
- Adding Mr values without multiplying by the number of atoms.
Practice Questions
Frequently Asked Questions
Where do I find atomic masses?
On the periodic table. Your exam usually provides one, so check what is given.
What is the formula for moles?
Moles = mass ÷ molar mass, where mass is in grams and molar mass is in g/mol.
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Reviewed by StudyMorrow editorial review on 5 Nov 2026.